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1995 WAEC Mathematics Theory (a) Using mathematical tables, find ; (i) \(2 \sin 63.35°\) ; (ii) \(\log \cos 44.74°\);...

Mathematics
WAEC 1995

(a) Using mathematical tables, find ; (i) \(2 \sin 63.35°\) ; (ii) \(\log \cos 44.74°\);

(b) Find the value of K given that \(\log K - \log (K - 2) = \log 5\);

(c) Use logarithm tables to evaluate \(\frac{(3.68)^{2} \times 6.705}{\sqrt{0.3581}}\)

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Explanation

(a)(i) \(\sin 63.35° = 0.8938\)

\(2 \sin 63.35° = 2 \times 0.8938 = 1.7876\)

(ii) \(\log \cos 44.74° = \bar{1}.8514\)

(b) \(\log K - \log (K - 2) = \log 5\)

\(\log (\frac{K}{K - 2}) = \log 5\)

\(\therefore \frac{K}{K - 2} = 5 \implies K = 5(K - 2)\)

\(K = 5K - 10 \implies 10 = 5K - K = 4K\)

\(K = 2\frac{1}{2}\)

(c) \(\frac{(3.68)^{2} \times 6.705}{\sqrt{0.3581}}\)

No Log
\((3.68)^{2}\) \(0.5658 \times 2 = 1.316\)
\(6.705\) \(0.8264  = 0.8264\)
 

= \(1.9580\)

\(\sqrt{0.3581}\) \(\bar{1}.5540 \div 2 = \bar{1}.7770\)
\(151.7\) \(\gets  2.1810\)

\(\therefore \frac{(3.68)^{2} \times 6.705}{\sqrt{0.3581}} = 151.7\)


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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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