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A.
4 sq units
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B.
2 sq units
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C.
\(\frac{4}{3}sq\hspace{1 mm}units\)
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D.
\(\frac{1}{3}sq\hspace{1 mm}units\)
Correct Answer: Option C
Explanation
\(y = x(2-x) \Rightarrow y= 2x - x^{2};
\int^{2}_{0}(2x-x^{2} = (x^{2}-\frac{x{3}}{3})^{2}\\
solving further gives (4 - \frac{1}{3} * 8) - (0) = \frac{4}{3} sq\hspace{1 mm}unit\)
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