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2000 WAEC Mathematics Theory (a) Evaluate and express your answer in standard form : \(\frac{4.56 \times 3.6}{0.12}\) (b) Without...

Mathematics
WAEC 2000

(a) Evaluate and express your answer in standard form : \(\frac{4.56 \times 3.6}{0.12}\)

(b) Without using mathematical tables or calculator, evaluate \((73.8)^{2} - (26.2)^{2}\).

(c) Simplify \(\sqrt{1\frac{19}{81}}\), expressing your answer in the form \(\frac{a}{b}\) where a and b are positive integers.

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Explanation

(a) \(\frac{4.56 \times 3.6}{0.12} \equiv \frac{4.56 \times 360}{12}\)

= \(4.56 \times 30 \)

= \(136.8 \)

= \(1.368 \times 10^{2}\)

(b) \((73.8)^{2} - (26.2)^{2}\)

Using the method of difference of two squares,

= \((73.8 + 26.2) \times (73.8 - 26.2)\)

= \(100 \times 47.6\)

= \(4760\)

(c) \(\sqrt{1\frac{19}{81}}\)

= \(\sqrt{\frac{100}{81}}\)

= \(\frac{10}{9}\)


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