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2012 WAEC Mathematics Theory (a)  In the diagram, /PQ/ = 6 cm, /QR/ = 13 cm, /RS/ = 5 cm...

Mathematics
WAEC 2012

(a)  In the diagram, /PQ/ = 6 cm, /QR/ = 13 cm, /RS/ = 5 cm and < RSQ is a right- angled triangle. Calculate, correct to one decimal place, /PS/.

(b)  The diagram show a wooden structure in the form of a cone mounted on a hemispherical base. The vertical height of the cone is 24 cm and the base radius 7 cm. Calculate, correct to 3 significant figures, the surface area of the structure. [Take \(\pi = \frac{22}{7}\)].

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Explanation

(a)   

\(\cos R = \frac{5}{13} = 0.3846\)

\(R = \cos^{-1} (0.3846) = 67.38°\)

\(/PS/^{2} = 5^{2} + 19^{2} - 2(5)(19)\cos 67.38\)

= \(25 + 361 - 190(0.3872)\)

= \(386 - 73.568\)

\(/PS/^{2} = 312.432\)

\(/PS/ = \sqrt{312.432}\)

= \(17.68 \approxeq 17.7 cm\)

(b) Slant height of a cone = \(l = \sqrt{7^{2} + 24^{2}}\)

\(\sqrt{49 + 576} = \sqrt{625}\)

= \(25 cm\)

C.S.A of a cone = \(\pi rl\)

= \(\frac{22}{7} \times 7 \times 25\)

= \(550 cm^{2}\)

Area of hemisphere = \(\frac{1}{2} \times 4\pi r^{2} = 2 \pi r^{2}\)

\(2 \times \frac{22}{7} \times 7 \times 7 = 308 cm^{2}\)

TSA of the structure = \(550 cm^{2} + 308 cm^{2} = 858 cm^{2}\)


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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC offline past questions - with all answers and explanations in one app - Download for free
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts