Correct Answer: Option A

Explanation

t = \(2^{-x} = \frac{1}{2^{x}}\)

\(\implies 2^{x} =\frac{1}{t}\)

\(2^{x+1} = 2^{x} \times 2^{1}\)

= \(\frac{1}{t} \times 2 = \frac{2}{t}\)

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