Make x the subject of the relation d = \(\sqrt{\frac{6}{x} - \frac{y}{2}}\)
a
x = \(\frac{6 + 12}{d^2 + y}\)
b
x = \(\frac{12}{d^2 - y}\)
c
x = \(\frac{12}{y} - 2d^2\)
d
x = \(\frac{12}{2d^2 + y}\)
Explanation
Correct Option
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