\(a^2 - b^2\)
\(b^2 - a^2\)
\(a^2b - ab^2\)
\(ab^2 - a^2b\)
Explanation
Video Explanation
No video available
Post your Contribution
Discussions (7)
i literally got this one correct!, and yall made it wrong. your system is rigged idc.
Given expression:
\[ \frac{a2b4 - b2a4}{ab(a+b)} \]
First, let's factor the numerator:
\[ a2b4 - b2a4 \]
This can be factored as:
\[ a2b4 - b2a4 = a2b2(b^2 - a^2) \]
Notice that
š
2
ā
š
2
is a difference of squares and can be factored further:
š
2
ā
š
2
=
(
š
ā
š
)
(
š
+
š
)
So, the factored form of the numerator is:
\[ a2b2(b - a)(b + a) \]
Now, let's rewrite the entire expression with the factored numerator:
\[ \frac{a2b2(b - a)(b + a)}{ab(a + b)} \]
Next, we can cancel out common factors in the numerator and the denominator. Notice that
š
š
in the denominator can be canceled with part of the
š
2
š
2
in the numerator. Also,
š
+
š
in the denominator can be canceled with
š
+
š
in the numerator:
\[ \frac{a2b2(b - a)(b + a)}{ab(a + b)} = \frac{ab(b - a)(b + a)}{a + b} \]
The
(
š
+
š
)
factors cancel out:
š
š
(
š
ā
š
)
1
=
š
š
(
š
ā
š
)
