Solved the equation \(2x^2 - x - 6\) = 0
\(2x^2 - x - 6\) = 0
\(2x^2 - 4x + 3x - 6\) = 0
2x(x - 2) + 3(x - 2) = 0
(2x + 3) (x - 2) = 0
Either; 2x + 3 = 0 or x - 2 = 0
x = \(\frac{-3}{2}\) or x = 2
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