Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

Leinad321

3 years ago

7!/(7-3)!3!
7×6×5×4×3×2/4!3!
7×6×5×4×3×2/4×3×2×3×2
=7×5=35
for vowel
4!/(4-2)!2!
4!/2!2!
4×3×2/2×2
=6
35×6=210

chapsycute

6 years ago

Wrong ansa
D is correct

Mich212

1 year ago

7c3 = (7 × 6 × 5)/(3×2×1) = 35
And
4C2 = (4×3)/(2×1) = 6

No. Of ways to arrange five different letters

5! = 5 × 4 × 3 × 2 × 1 = 120

Total no. Of words is:
35 × 6 × 120 = 25200

Answer: 25200..
Myschool take note

RENEGADE10

3 months ago

210 only represents the number of ways to choose the letters na
Now to form words we must arrange them and since we have 5 lettersd that is 5! which is 120 multiplied by 210
thats going to give us 25,200
Please help me confirm