Evaluate ∫\(^2_1\) \(\frac{5}{x}\) dx
∫\(\frac{5}{x}\) dx = 5 ∫\(\frac{1}{x}\) = 5Inx
Since the integral of \(\frac{1}{x}\) is Inx
∫\(^2\) \(_1\)∫ \(\frac{5}{x}\) dx = 5
dx = 5 (In<2 – InIn1)
= 3.4657
= 3.47
There is an explanation video available below.
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