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Evaluate log\(_2\) 8 – log\(_3\) \(\frac{1}{9}\)

Mathematics
JAMB 2018

Evaluate log\(_2\) 8 – log\(_3\) \(\frac{1}{9}\)

  • A. -1 1\(\frac{1}{2}\)
  • B. -1
  • C. 1
  • D. 5
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Correct Answer: Option D
Explanation

log\(_2\) 8 – log\(_3\) \(\frac{1}{9}\)

  = log \(_2\) 2\(^3\) – log\(_3\) 9\(^{-1}\)

  = log\(_2\) 2\(^3\) – log\(_3\) 3\(^{-2}\)

  Based on law of logarithm

  = 3 log\(_2\) 2 – (-2 log\(_3\) 3)

  But log\(_2\) 2 = 1,

  log\(_3\) 3 = 1

  So, = 3 + 2

  = 5

There is an explanation video available below.


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Explanation Video

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