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A.
3x\(^3\) - 2x\(^2\) + x + c
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B.
2x\(^3\) - x\(^2\) + x + c
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C.
2x\(^3\) – 3x\(^2\) + c
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D.
x\(^3\) + x\(^2\) – x + c
Correct Answer: Option B
Explanation
6x\(^2\) - 2x + 1
\(\frac{6x^{2+1}}{2+1} - \frac{2x^{1+1}}{1+1}+ 1x = \frac{6x^3}{3} - \frac{2x^2}{2} + x\)
\(2x^3 - x^2 + x + c\)
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