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Integrate the expression 6x\(^2\) - 2x + 1

Mathematics
JAMB 2018

Integrate the expression 6x\(^2\) - 2x + 1

  • A. 3x\(^3\) - 2x\(^2\) + x + c
  • B. 2x\(^3\) - x\(^2\) + x + c
  • C. 2x\(^3\) – 3x\(^2\) + c
  • D. x\(^3\) + x\(^2\) – x + c
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Correct Answer: Option B
Explanation

6x\(^2\) - 2x + 1

\(\frac{6x^{2+1}}{2+1} - \frac{2x^{1+1}}{1+1}+ 1x = \frac{6x^3}{3} - \frac{2x^2}{2} + x\)

\(2x^3 - x^2 + x + c\)

There is an explanation video available below.


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Explanation Video

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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709