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Make T the subject of the relation.

Mathematics
JAMB 2018

Make T the subject of the relation.

  • A. T = \(\frac{R + P3}{15Q}\)
  • B. T = \(\frac{R - 15P^3}{Q}\)
  • C. T =R - \(\frac{15P^3}{Q}\)
  • D. T = \(\frac{15R + Q}{P^3}\)
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Correct Answer: Option C
Explanation

P = (\(\frac{Q( R - T )}{ 15})^\frac{1}{3}\)

take cube of both sides

\(P^3 =\frac{Q( R - T)}{ 15}\)

cross multiply

\(15P^3 = Q( R - T)\)

\(\frac{15P^3}{Q}\) = R - T 

T = R - \(\frac{15P^3}{Q}\) 

There is an explanation video available below.


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Explanation Video

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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
WAEC offline past questions - with all answers and explanations in one app - Download for free