In a class of 40 students, 32 offer Mathematics, 24 offer Physics and 4 offer neither Mathematics nor Physics. How many offer both Mathematics and Physics?
Let the number of people that offer both Mathematics and Physics = y
Then, \((32 - y) + y + (24 - y) + 4 = 40\)
\(60 - y = 40 \implies y = 20\)
\(\therefore\) 20 students offer both Mathematics and Physics.
There is an explanation video available below.
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