Correct Answer: Option C

Explanation

Area of \(\Delta\) QNP = \(\frac{1}{2} \times 9 \times 6 \) = 27cm²

Area of \(\Delta\) QMN = Area of \(\Delta\) QNP

= Area of \(\Delta\) PNO (triangles between the same parallels)

Hence, area of the trapezium

3 x area of \(\Delta\) QNP

= 3 x 27

= 81cm²

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