Mathematics
WAEC 2016
In the diagram, TS is a tangent to the circle at S. |PR| and < PQR = 177
o. Calculate < PST.
-
A.
54o
-
B.
44o
-
C.
34o
-
D.
27o
Correct Answer: Option A
Explanation
In the diagram above, x
1 = 180
o - 117
o = 63
o(opposite angles of a cyclic quad.)
x
1 = x
2 (base angles of isos. \(\Delta\))
x
1 + x
2 + \(\alpha\) = 180
o (sum of angles of a \(\Delta\)
63
o + 63
o + \(\alpha\) = 180
o
\(\alpha\) = 180
o - (63 + 63)
o
= 54
o
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