Mathematics
WAEC 2015
In the diagram, \(\bar{OX}\) bisects < YXZ and \(\bar{OZ}\) bisects < YZX. If < XYZ = 68
o, calculate the value of < XOZ
-
A.
68o
-
B.
72o
-
C.
112o
-
D.
124o
Correct Answer: Option D
Explanation
In \(\Delta\) XYZ, 2m + 2n + 68
o = 180
o
2(m + n) + 68
o = 180
o...(1)
in \(\Delta\) XOZ, m + n + q = 180
o ...(2)
(m + n) = 180
o - q...(3)
substituting 180
o - q for (m + n) in (1) gives
2(180
o - q) + 68
o = 180
o
360
o - 2q = 180
o - 68
o
360
o - 2q = 112
o
360
o - 112
o = 2q
248
o = 2q
q = \(\frac{248^o}{2}\)
= 124
o
hence, < XOZ = 124
o
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