\(\begin{array}{c|c}
x & 0 & 1\frac{1}{4} & 2 & 4\\
\hline
y & 3 & 5\frac{1}{2} & &
\end{array}\)
The table given shows some values for a linear graph. Find the gradient of the line
Ler: (x1, y1) = (0, 3)
(x2, y2) = (\(\frac{5}{4}, \frac{11}{2}\))
Using gradient, m = \(\frac{y_2 - y_2}{x_2 - x_1}\)
= \(\frac{\frac{11}{2} - 3}{\frac{5}{4} - 0}\)
= \(\frac{11 - 6}{2} + \frac{5}{4}\)
= \(\frac{5}{} + \frac{5}{4}\)
= \(\frac{5}{2} \times \frac{4}{5}\)
= 2
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