Given that logx 64 = 3, evaluate x log\(_2\)8
If logx 64 = 3, then \(64 = x^3\) \(4^3 = x^3\) Since the indices are equal, x = 4 Hence, x log\(_2\)8 = 4(3.log\(_2\)2) = where log\(_2\)2 = 1(1) = 12 X 1
= 12
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