Correct Answer: Option B

Explanation

\(\frac{27^x \times 3^{1 - x}}{9^{2x}} = 1\)

\(\frac{3^{3x} \times 3^{1 - x}}{3^{2(2 - x)}} = 3^0\)

\(3^{3x} \times 3^{1 - x} \div 3^{4x} = 3^0\)

\(3^{(3x + 1 - x - 4x)} = 3^0\)

\(3^{(1 - 2x)} = 3^0\)

since the bases are equal,

1 - 2x = 0

- 2x = -1

x = \(\frac{1}{2}\)

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