\(\begin{array}{c|c}
Scores & 3 & 6 & 5 & 2 \\
\hline
Frequency & 2 & 3 & 4 & 6
\end{array}\)
From the table above, find the median
3
5
4
6
Explanation
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Discussions (31)

LISTEN CAREFULLY EVRYBODY U RE WRNG D CRRCT ANS IS " 3 " THIS IS MY FANTASTIC SOLUTION
WE RE ASKED TO FIND D MEDIAN ONLY
FIRST ARRNGE D TABLE BY AVIN
.: SCORE(X) FREQ CUMLTV FREQ position of x
2 6 6 1, 2, 3, 4, 5, 6
3 2 6+2=8 7, 8
5 4 8+4=12 9, 10, 11, 12
6 3 12+3=15 13, 14, 15
£f=15
in d abov table cumulative frequency (i.e. Addin d preceedin frequency 2 d successive frequency).
position of (i.e. The range in d units dat each item occupies e.g 2 occupies spaces 1, 2, 3, 4, 5, nd 6, item 3 occupies spaces 7 nd 8 nd so on to item 6 whch occupies spaces 13, 14, nd 15.
THE MEDIAN = (N/2)th item
i.e. the total number divided by 2
MEDIAN = (15/2)the items
MEDIAN =7.5th item ~ 8th items
in d table, d item dat occupies 8th position is 3. THEREFORE THE MEDIAN IS 3.

The selected answer is wrong:
the median was asked for not the mean. It should be 5

i don't think the ans is correct,they asked for the MEDIAN"the middle term" Not MEAN Value

median= n+1/2. where n=total number of data(frequency in this case)
2+3+4+6+1/2=16/2=8
therefore the median is in the value of 8th frequency score i.e when you add the frequency the scores that falls in that range is the median=5

I think the answer is correct if u solve d scores 3+5=8/2=4 corre t me if u feel it is wrong

wen u expand from d freq table u get 3,3,6,6,6,5,5,5,5,2,2,2,2,2,2. Rearranging according to increasing order u get 2,2,2,2,2,2,3,3,5,5,5,5,6,6,6. Then applying basic knowledge d middle number is 3 simple. Tanx

Your answer is wrong.
The correct answer is '3'
Don't you know you have to rearrange it before finding the median?
The scores are given as 3 6 5 2
You have to rearrange in ascending order
2 3 5 6
@myschool, please correct this.

@Roxanne george, the answer is nt correct.
THE ANSWER IS 5....CHECK MY SOLVING ABOVE.




