Evaluate \(\int\)(cos4x + sin3x)dx
a
sin4x - cos3x + k
b
sin4x + cos3x + k
c
\(\frac{1}{4}\)sin4x - \(\frac{1}{3}\)cos3x + k
d
\(\frac{1}{4}\)sin4x + \(\frac{1}{3}\)cos3x + k
Explanation
Correct Option
cVideo Explanation
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Chimemeria
9 years ago
շ(cos4x+sin3x)dx
շcos4xdx+sin3xdx
let u=4x and let u2=3x
du/dx=4......& du2/dx2=3
dx=du/4 and dx2=du2/3
int...cos u.du/4+ sin u.du/3
int.1/4cos u.du+int.1/3sinu.du
1/4sinu +(-1/3)cos u +k
1/4sin4x-1/3cos3x+k
