Find the derivative of y = ( \(\frac{1}{3}\)X + 6)\(^2\)
a
2( \(\frac{1}{3}\)X + 6
b
\(\frac{2}{3}\) ( \(\frac{1}{3}\)X + 6)
c
\(\frac{2}{3}\) ( \(\frac{1}{3}\)X + 6)2
d
\(\frac{1}{3}\) ( \(\frac{1}{3}\)X + 6)2
Explanation
Correct Option
bVideo Explanation
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Michealubegirl
5 years ago
using chain rule for the question
u have
y=(1÷3x + 6)^2
u=1÷3x+6
v=u^2
du/dy=1÷3
dv/dy=2u
note: u=(1÷3x+6)
du/dy*dv/dy=1÷3*2u
=1÷3*2(1÷3x+6)
=2÷3(1÷3x+6)
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