x varies directly as y and inversely as z. when x = 5, y = 2 and z = 1. What is the value of x when y = 5 and z = 2?
x = \(\frac{ Ky}{z}\)
x = 5, y = 2 and z = 1
x = \(\frac{ Ky}{z}\)
5 = \(\frac{ K2}{1}\)
K = \(\frac{5}{2}\) = 2.5
find x when y = 5 and z = 2
x = \(\frac{2.5 \times5}{2}\)
x = \(\frac{12.5}{2}\) = 6.25.
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