If y\(^2\)+ 14y + k is a perfect square, then k =
y\(^2\)+ 14y + k
let a = 1, b = 14, c = k (where a and b represent the coefficient of y and y\(^2\) respectively)
4ac = b\(^2\)
4 x 1 x c = 14 x 14 = 196
4c = 196
c = \(\frac{196}{4}\) = 49
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