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If y\(^2\)+ 14y + k is a perfect square, then k =

Mathematics
NECO 2005

If y\(^2\)+ 14y + k is a perfect square, then k =

  • A. 4
  • B. 7
  • C. 28
  • D. 49
  • E. 196
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Correct Answer: Option D
Explanation

y\(^2\)+ 14y + k

let a = 1, b = 14, c = k (where a and b represent the coefficient of y and y\(^2\) respectively)

4ac = b\(^2\)

4 x 1 x c = 14 x 14 = 196

4c = 196

c = \(\frac{196}{4}\) = 49


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