Two fair dice are tossed together once. What is the probability of getting a total of at least 9 from the outcome?
a
\(\frac{1}{9}\)
b
\(\frac{1}{6}\)
c
\(\frac{5}{18}\)
d
\(\frac{1}{3}\)
e
\(\frac{13}{18}\)
Explanation
Correct Option
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Discussions (2)
Aloma777
2 years ago
The questions says at least 9, so 6:5,6:6,6:4,6:3,3:6,4:6,5:6,6:6,5:4,5:5 making 10 possibilities = 10/36 or 5/18
Chikeziehenry
5 years ago
It is 1/9 my school please correct it it is 6;3;5;3;3;6;4;5;5;4 it is 5/36 I mean from the outcome
