T varies directly as D and inversely as A. Given that T = 6, D = 3, and A = 2, find A when T = 3 and D = 6.

a

4

b

6

c

8

d

12

e

24

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T=KD/A
where k=constant
make k subject formular
k=TA/D
T=6 D=3 A=2
Therefore. k=6×2 / 3
k=12/3=4
when T=3 AND D=6
A=kD/T =4×6/3 =24/3 =8

Brainiac6
1 year ago

Englis

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