6, 9, 10, 8 and 7
S.D = \(\sqrt{V}\)
S.D = standard deviation, V = variance
V = \(\frac{\sum({x - \overline{x})^2}}{n}\)
Mean(\(\overline{x}\)) = \(\frac{6 + 9 + 10 + 8 + 7}{5}\) = 8
| x | x - \(\overline{x}\) |
(x - \(\overline{x}\))\(^2\) |
| 6 | 6 - 8 = -2 | 4 |
| 9 | 9 - 8 = 1 | 1 |
| 10 | 10 - 8 = 2 | 4 |
| 8 | 8 - 8 = 0 | 0 |
| 7 | 7 - 8 = -1 | 1 |
TOTAL = 10
V = \(\frac{\sum({x - \overline{x})^2}}{n}\) = \(\frac{10}{5}\) = 2
S.D = \(\sqrt{V}\) = \(\sqrt{2}\) = 1.414 ≈ 1.4
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