A bag Contains 2 red, 3 blue and 4 green identical balls. If two balls are picked at random one after the other without replacement, what is the probability that both are green?
a
\(\frac{1}{6}\)
b
\(\frac{1}{3}\)
c
\(\frac{16}{18}\)
d
\(\frac{3}{8}\)
e
\(\frac{4}{9}\)
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Lota256
8 months ago
Given:
Red = 2
Blue = 3
Green = 4
Total balls = 2 + 3 + 4 = 9
Step 1: Probability of the first green
= 4/9
Step 2: Probability of the second green (after the first green has been taken)
= 3/8
Step 3: Multiply the two probabilities
= 4/9 x 3/8 = 1/6
