A bag contains p dozens of bananas and 3q of these proved to be bad. If I buy one third of the goods ones, how many do I get?

a

P -3q

b

\(\frac{1}{3}\) (p - 3q)

c

3q

d

4p - q

e

12p - 3q

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Davyboi
4 years ago

1 dozen = 12,

p dozen(s) of banana = 12p

3q are bad

Let the good banana be r

bad banana (3q) + good banana (r) = total banana (12p)

3q + r = 12p

r = 12p - 3q

the good banana = 12p - 3q

if i buy just one third, this becomes:

= 1/3 (12p - 3q)

= 4p - q

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