Divide the LCM of 15abc and 20a\(^2\)bc by their HCF
LCM of 15abc and 20a\(^2\)bc = 60a\(^2\)bc
Factors of 15abc = 1, 3, 5,15, a, b, c
and of 20a\(^2\)bc = 1, 2, 4, 5, 10, 20, a, b, c
HCF of 15abc and 20a\(^2\)bc = 5abc
→ LCM ÷ HCF = 60a\(^2\)bc ÷ 5abc
= 12a
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