If the first term of an AP is 1.2 and the common difference is also 2, what is the mean of the first five terms?
Given the first term \( a = 1.2 \) and common difference \( d = 2 \), the first five terms of the AP are:
\(a_1 = 1.2\)
\(a_2 = 1.2 + 2 = 3.2\)
\(a_3 = 1.2 + 4 = 5.2 \)
\(a_4 = 1.2 + 6 = 7.2 \)
\(a_5 = 1.2 + 8 = 9.2\)
The sum of the first five terms is:
\(\text{Sum} = 1.2 + 3.2 + 5.2 + 7.2 + 9.2 = 26\)
The mean is calculated as:
\(\text{Mean} = \frac{26}{5} = 5.2\)
Thus, the mean of the first five terms is \(5.2\).
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