If sin θ = \(\frac{\sqrt{3}}{2}\) and 0 < θ < 180°, what is cos θ ?

a

\(\frac{1}{\sqrt{3}}\)

b

\(\frac{2}{\sqrt{3}}\)

c

\(\frac{1}{2}\)

d

\(\frac{\sqrt{3}}{2}\)

e

\(\sqrt{3}\)

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Shushino
2 years ago

θ= Sin^-1 ((3√2)/2)
= 60°
Cos(60)=1/3

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