The probability that a student will pass a mathematics test is ⅗. If 3 students are chosen at random, what is the probability that at least 2 of them will pass the test?
a
\(\frac{27}{125}\)
b
\(\frac{9}{25}\)
c
\(\frac{72}{125}\)
d
\(\frac{76}{125}\)
e
\(\frac{81}{125}\)
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TheGuru
3 years ago
P(1)= 3/5
P(at least 2)= P(3) or P(2)
P(at least 2)= (3/5)³ + ({3/5}³-{1-3/5})
P(at least 2) = 27/125 + 54/125
P(at least 2) = 81/125
