Correct Answer: Option D

Explanation

Let the two parallel chords be AB = 46 cm and CD = 40 cm.  
Radius of the circle, r = 25 cm.  
The centre  O lies between the two chords.

Draw perpendiculars from O to the chords (these perpendiculars bisect the chords).

- Half of AB = 23 cm  
- Half of CD = 20 cm

Distance from centre to each chord:

For chord AB (46 cm):  
d\(_1 = \sqrt{r^2 - 23^2} = \sqrt{625 - 529} = \sqrt{96} = 4\sqrt{6} \approx 9.80 \text{ cm}\)

For chord CD (40 cm):  
d\(_2 = \sqrt{r^2 - 20^2} = \sqrt{625 - 400} = \sqrt{225} = 15 \text{ cm}\)

Since the centre lies between the two chords, the distance between the chords is: d\(_1 + d_2 = 4\sqrt{6} + 15 \text{ cm}\)

Approximate value: ≈ 24.80 cm

• when will waec gce registration close and how much is it for 2026? Answer this

  1 Answers   ·   1 day ago
• when is mop up exam starting? Answer this

  2 Answers   ·   4 days ago
• if my aggregate is 65 percent can I study economic in lasu? Answer this

  1 Answers   ·   1 day ago