In an acute angle-triangle XYZ, XZ = 9cm, YZ = 11cm and ∠XZY = 35° Calculate ∠YXZ, correct to the nearest degree.

sogundare

5 years ago

Please i need proper explanation

kolawoleolaoluwa

3 years ago

Using sine rule
SINA/a= SINC/c
Arrange the triangle
X
/\
9 / \
/ 11 \
SINA/a = SINC/c
SINA/11 = SIN 35°/9
Cross multiply
11×SIN35 = 9×SINA
Divide both sides by 9
11×0.5736/9= SINA
SINA= 0.7011
A= SIN`¹ 0.7011
A= 44.5°
A= 45° (To the nearest degree)
The ans is (b)

JerryQ123

3 years ago

First of all look for side xy. Then use sine rule.

Ott_2

1 year ago

The correct answer is E. Solve it using cosine rule and sine rule

stehllaN

2 years ago

using cosine rule to get side XY, then using sine rule to get angle yxz that's 89.17.

uthmanzy

2 years ago

hw can we use sine rule under exam tension when they are not special angles

ediepie2008

3 months ago

I need a good explanation

kevwe7

1 year ago

wry

Kimoyo

1 year ago

I think there was a mistake in the calculation of....
ZX². Meanwhile, ZX was 9cm, so if it was squared, it was supposed to be 9²=81....not 9²=92.
Thank you

CharLes78

3 years ago

The formula is A/sina=B/sinb

kolawoleolaoluwa

3 years ago

Using sine rule
SINA/a= SINC/c
Arrange the triangle
X
/\
9 / \
/ 11 \
SINA/a = SINC/c
SINA/11 = SIN 35°/9
Cross multiply
11×SIN35 = 9×SINA
Divide both sides by 9
11×0.5736/9= SINA
SINA= 0.7011
A= SIN`¹ 0.7011
A= 44.5°
A= 45° (To the nearest degree)