Two beads are drawn at random, one after the other, with replacement, from a box containing 5 red and 7 white identical beads. What is the probability that the beads are the same colour
a
\(\frac{119}{144}\)
b
\(\frac{95}{144}\)
c
\(\frac{37}{72}\)
d
\(\frac{49}{144}\)
e
\(\frac{1}{6}\)
Explanation
Correct Option
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Discussions (8)
12345royal
2 years ago
The answer is as follows.
n(red)=5
n(white)=7
total=12
therefore the probability of finding a red ball is 5/11
while the probability of finding a white ball is 7/12
therefore probability the both are the same colour is =
5/12×5/12+7/12×7/12=37/72
therefore answer is 37/72
option C
AsherOscar001
1 year ago
I got my answer 1/6 and I know it is correct so what happened to the explanation.
