Find the value of k such that \(t^2\) + kt + \(\frac{25}{4}\) is a perfect square
a
5
b
3
c
\(\frac{5}{2}\)
d
\(\frac{5}{4}\)
e
\(\frac{1}{5}\)
Explanation
Correct Option
aVideo Explanation
No video available
Post your Contribution
Share:
Discussions (7)
Afakriya
4 months ago
From your general formula
x=-(b)+-√b^2-4ac/a
then use
b^2-4ac
which
b^2=4ac
and you are given a=4 b=k
c=25/4
so
k^2=4×1×25/4
4 cancel 4
k^2=25
k=√25
so
k=5
Afakriya
4 months ago
From your general formula
x=-(b)+-√b^2-4ac/a
then use
b^2-4ac
which
b^2=4ac
and you are given a=4 b=k c=25/4
