Given that \(\frac{(3 - y)}{2x}\) = \(\frac{(6y + 7)}{(4x - 5)}\), find the value of x when y = 2
\(\frac{64}{5}\)
6
\(\frac{5}{34}\)
\(\frac{-5}{34}\)
\(\frac{-64}{5}\)
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Discussions (11)
(3-2)/2x=(6*2+7)/(4x-5)
1/2x=19/4x-5
4x-5=19*2x
4x-5=38x
4x-38x=5
-34x=5
x=-5/34
option d
[3-y]/2x=[6y+7/[4x-5]
cross multiply
then it go like this
(3-y)(4x-5)=2x(6y+7)
then fatorise
12x-15-14xy+5y=4xy+14x
collect like terms
12x-14x+5y=12xy+4xy+15
-2x+5y=16xy+15
when y=2
substitute y=2
-2x+5(2)=16x(2)+15
-2x+10=32x+15
-2x-32x=15-10
-34x=5
divide both sides by -34
-34x/-34=5/-34
x=-5/-34
your y=3,x=5/4
input these values into d equation you have, 1/2x=19/4x-5
cross multiply then solve.
your final answer is -5/34
your y=3,x=5/4
input these values into d equation you have, 1/2x=19/4x-5
cross multiply then solve.
your final answer is -5/34.
