Find the 19th term of the A.P. \(\frac{5}{6}\), \(\frac{8}{6}\), \(\frac{11}{6}\).................
a
7\(\frac{1}{2}\)
b
9
c
9\(\frac{1}{2}\)
d
9\(\frac{5}{6}\)
e
10
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elmira
5 years ago
Un=a+(n-1)d
U1=a+(1-1)d
5/6=a+(1-1)d
5/6=a+0
therefore, a=5/6
U2=a+(2-1)d
8/6=(5/6)+d
d=(8/6) - (5/6)
d=1/2
U19=(5/6)+18(1/2)
U19=(5/6)+9
U19=59/6
