Evaluate log5(\( y^2x^5 ÷ 125b½) \)

Mrnoah

1 year ago

To evaluate this expression, we'll use logarithmic properties:

log₅(y²x⁵ ÷ 125b½)

First, rewrite 125 as 5³:

log₅(y²x⁵ ÷ 5³b½)

Now, apply logarithmic properties:

log₅(y²) + log₅(x⁵) - log₅(5³) - log₅(b½)

Using the power rule:

2log₅(y) + 5log₅(x) - 3 - (1/2)log₅(b)

This is the simplified expression. Without specific values for x, y, and b, we can't further simplify.