Make x the subject of the equation
s = 2 + \(\frac{t}{5} \)(x + ⅗y)

a

x = 5[(s − 2) ÷ t] - 3/5y

b

x = 25[(s − 2) ÷ t] − 3ty

c

x = [1 ÷ (s − 2)3ty]

d

x = [5(s − 2) 2 ÷ 3ty] × t

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Rebelx12
4 years ago

S= 2+ t/5(x+3/5y)
multiply through by 5
5S = 10 + t(x +3/5y)
5s = 10 + tx + 3/5ty
make tx subject of the formula
tx = 5s - 10 -3/5ty
divide both sides by t
x = 5(s -2)/t -3/5y

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