If a number is selected at random from each of the sets p = {1, 2, 3} and Q = {2, 3, 5}, find the probability that the sum of the numbers is prime
a
\(\frac{5}{9}\)
b
\(\frac{4}{9}\)
c
\(\frac{1}{3}\)
d
\(\frac{2}{9}\)
Explanation
Correct Option
bVideo Explanation
No video available
Post your Contribution
Share:
Discussions (4)
Grace1244
4 years ago
My school, the correct option is 4/9
You failed to take 7 into consideration as a prime number
Odeomu
1 year ago
because I was solving in my prep50 and I saw this same question but the answer in the prep50 says option b which is 4/9. I want to know the reason for the answer being 3/9 and the detailed explanation
