Correct Answer: Option B

Explanation

let the chord be AB = 7cm

radius OA = 3.7cm distance of the = OM using Pythagoras theorem

OA² = AM² + OM²

3.7² = 3.5² + OM²

13.69 = 12.25 + OM²

13.69 - 12.25 = OM²

1.44 = OM²

OM = \(\sqrt{1.44}\)

OM = 1.2cm

distance of chord = 1.2cm

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