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Find the values of k in the equation 6k2 = 5k + 6

Mathematics
WAEC 2013

Find the values of k in the equation 6k2 = 5k + 6
  • A. {\(\frac{-2}{3}, \frac{-3}{2}\)}
  • B. {\(\frac{-2}{3}, \frac{3}{2}\)}
  • C. {\(\frac{2}{3}, \frac{-3}{2}\)}
  • D. {\(\frac{2}{3}, \frac{3}{2}\)}
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Correct Answer: Option B
Explanation
6k2 = 5k + 6

6k2 - 5k - 6 = 0

6k2 - 0k + 4k - 6 = 0

3k(2k - 3) + 2(2k - 3) = 0

(3k + 2)(2k - 3) = 0

3k + 2 = 0 or 2k - 3 = 0

3k = -2 or 2k = 3

k = \(\frac{-2}{3}\) or k = \(\frac{3}{2}\)

k = (\(\frac{-2}{3}\), k = \(\frac{3}{2}\))

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