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Given that \(p^{\frac{1}{3}}\) = \(\frac{\sqrt[3]{q}}{r}\), make q the subject of the equation

Mathematics
WAEC 2013

Given that \(p^{\frac{1}{3}}\) = \(\frac{\sqrt[3]{q}}{r}\), make q the subject of the equation

  • A. q = p\(\sqrt{r}\)
  • B. q = p3r
  • C. q = pr3
  • D. q = pr\(\frac{1}{3}\)
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Correct Answer: Option C
Explanation

\(p^{\frac{1}{3}}\) = \(\frac{\sqrt[3]{q}}{r}\)

          cross multiply
\(p^{\frac{1}{3}}\) = \(\frac{q^{1/3}}{r}\)

r\(p^{\frac{1}{3}}\) =  \(q^{\frac{1}{3}}\)

take the cube of both sides

 \((rp^{\frac{1}{3}})^3\) =  \((q^{\frac{1}{3}})^3\)

\(r^3p^{\frac{3}{3}}\) = \(q^{\frac{3}{3}}\)

\(r^3\)p = q

 ∴ q = p\(r^3\)

 


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