Make p the subject of the relation: q = \(\frac{3p}{r} + \frac{s}{2}\)
a
p = \(\frac{2q - rs}{6}\)
b
p = 2qr - sr - 3
c
p = \(\frac{2qr - s}{6}\)
d
p = \(\frac{2qr - rs}{6}\)
Explanation
Correct Option
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