Correct Answer: Option D

Explanation

cos x^o = \(\frac{1}{r}\); \(\sqrt{r^2 - 1}\)

By Pythagoras r² = 1² + x² - 1

x = \(\sqrt{r^2 - 1}\)

tan x^o = \(\sqrt{r^2 - 1}\)

= \(\sqrt{r^2 - 1}\)

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