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Given that tan x = 1, where 0o \(\geq\) x 90o, evaluate \(\frac{1 - \sin^2...

Mathematics
WAEC 2010

Given that tan x = 1, where 0o \(\geq\) x 90o, evaluate \(\frac{1 - \sin^2 x}{\cos x}\)
  • A. 2\(\sqrt{2}\)
  • B. \(\sqrt{2}\)
  • C. \(\frac{\sqrt{2}}{2}\)
  • D. \(\frac{1}{2}\)
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Correct Answer: Option C
Explanation
Given tan x = 1

x = tan-1(1)

x = 45o

Now, \(\frac{1 - ( \frac{1}{\sqrt{2} )^2}}{\frac{1}{\sqrt{2}}}\)

= \(\frac{1 - \frac{1}{2}}{\frac{1}{2}}\)

= \(\frac{1}{2} + \frac{1}{\sqrt{2}}\)

= \(\frac{1}{2} \times \frac{1}{\sqrt{2}}\)

= \(\frac{\sqrt{2}}{2}\)

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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
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