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If sin 3y = cos 2y and 0o \(\leq\) 90o, find the value of y

Mathematics
WAEC 2010

If sin 3y = cos 2y and 0o \(\leq\) 90o, find the value of y
  • A. 18o
  • B. 36o
  • C. 54o
  • D. 90o
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Correct Answer: Option A
Explanation
sin 3y = cos 2y, but sin \(\theta\) = cos(90 - \(\theta\))

sin 3y = cos(90 - 3y)

cos(90 - 3y) = cos 2y

90 - 3y = 2y

5y = 90

y = \(\frac{90}{5}\)

y = 18o

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